Solving Quadratic Equations ┃Middle Term Splitting
Middle Term Splitting
Benefits:
This method requires much less calculation and effort. It is solved in a quicker and cleaner method.
Drawbacks:
Unlike the quadratic formula, the middle term splitting method only works in certain cases.
How does it work:
ax² + bx + c
This method will only work if there are two numbers that add up to 'b' and have a product of 'a*c'
What we do is we write the equation in another form and factorise it into two parts which equal zero. The examples below will explain better!
Here, 6 and -5 are the two numbers needed. They are the set of numbers which add up to the origibal 'b' whoch was 1, and form a product of -30( a*c)! After that the equation was just factorised. Since this would equal to zero, we would get two sub equations:
x-5=0 and x+6=0
From here, we know the answers of the quadratic equation are 5 and -6!
In this case we need a set of numbers that multiply to 24 and add up to 5, thus, 8 and -3! Now we follow the same method as before and get the solutions/ roots as 3/2 and -4!
Questions
x2 -8x -9
Solution:
The middle term needs to be split into two terms whose product is -9x2 while the sum remains -8x
x2 - 9x + 1x -9
= x(x - 9) + 1 (x - 9)
= (x - 9) (x + 1)
x2 +13x -168
Solution:
The middle term needs to be split into two terms whose product is -168x2 while the sum remains +13x
x2 + 21x - 8x -168
= x(x + 21) - 8 (x + 21)
= (x + 21) (x - 8)
x2 +3x -40
Solution:
The middle term needs to be split into two terms whose product is -40x2 while the sum remains +3x
x2 + 8x - 5x -40
= x(x + 8) - 5 (x + 8)
= (x + 8) (x - 5)
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